Optimal. Leaf size=59 \[ \frac {2 i (a+i a \tan (c+d x))^{5/2}}{5 a^3 d}-\frac {4 i (a+i a \tan (c+d x))^{3/2}}{3 a^2 d} \]
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Rubi [A] time = 0.06, antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3487, 43} \[ \frac {2 i (a+i a \tan (c+d x))^{5/2}}{5 a^3 d}-\frac {4 i (a+i a \tan (c+d x))^{3/2}}{3 a^2 d} \]
Antiderivative was successfully verified.
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Rule 43
Rule 3487
Rubi steps
\begin {align*} \int \frac {\sec ^4(c+d x)}{\sqrt {a+i a \tan (c+d x)}} \, dx &=-\frac {i \operatorname {Subst}\left (\int (a-x) \sqrt {a+x} \, dx,x,i a \tan (c+d x)\right )}{a^3 d}\\ &=-\frac {i \operatorname {Subst}\left (\int \left (2 a \sqrt {a+x}-(a+x)^{3/2}\right ) \, dx,x,i a \tan (c+d x)\right )}{a^3 d}\\ &=-\frac {4 i (a+i a \tan (c+d x))^{3/2}}{3 a^2 d}+\frac {2 i (a+i a \tan (c+d x))^{5/2}}{5 a^3 d}\\ \end {align*}
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Mathematica [A] time = 0.23, size = 65, normalized size = 1.10 \[ -\frac {2 (3 \tan (c+d x)+7 i) \sec ^2(c+d x) (\cos (2 (c+d x))+i \sin (2 (c+d x)))}{15 d \sqrt {a+i a \tan (c+d x)}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.63, size = 76, normalized size = 1.29 \[ \frac {\sqrt {2} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} {\left (-16 i \, e^{\left (5 i \, d x + 5 i \, c\right )} - 40 i \, e^{\left (3 i \, d x + 3 i \, c\right )}\right )}}{15 \, {\left (a d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, a d e^{\left (2 i \, d x + 2 i \, c\right )} + a d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (d x + c\right )^{4}}{\sqrt {i \, a \tan \left (d x + c\right ) + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.20, size = 73, normalized size = 1.24 \[ -\frac {2 \left (4 i \left (\cos ^{2}\left (d x +c \right )\right )-4 \cos \left (d x +c \right ) \sin \left (d x +c \right )+3 i\right ) \sqrt {\frac {a \left (i \sin \left (d x +c \right )+\cos \left (d x +c \right )\right )}{\cos \left (d x +c \right )}}}{15 d \cos \left (d x +c \right )^{2} a} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.32, size = 79, normalized size = 1.34 \[ -\frac {2 i \, {\left (15 \, \sqrt {i \, a \tan \left (d x + c\right ) + a} - \frac {3 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {5}{2}} - 10 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {3}{2}} a + 15 \, \sqrt {i \, a \tan \left (d x + c\right ) + a} a^{2}}{a^{2}}\right )}}{15 \, a d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.31, size = 155, normalized size = 2.63 \[ -\frac {8\,\sqrt {\frac {a\,\left (\cos \left (2\,c+2\,d\,x\right )+1+\sin \left (2\,c+2\,d\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,c+2\,d\,x\right )+1}}\,\left (\cos \left (2\,c+2\,d\,x\right )\,27{}\mathrm {i}+\cos \left (4\,c+4\,d\,x\right )\,9{}\mathrm {i}+\cos \left (6\,c+6\,d\,x\right )\,1{}\mathrm {i}-5\,\sin \left (2\,c+2\,d\,x\right )-4\,\sin \left (4\,c+4\,d\,x\right )-\sin \left (6\,c+6\,d\,x\right )+19{}\mathrm {i}\right )}{15\,a\,d\,\left (15\,\cos \left (2\,c+2\,d\,x\right )+6\,\cos \left (4\,c+4\,d\,x\right )+\cos \left (6\,c+6\,d\,x\right )+10\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{4}{\left (c + d x \right )}}{\sqrt {i a \left (\tan {\left (c + d x \right )} - i\right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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